php - JQUERY AJAX LOAD Function Error -


मैं jquery ajax लोड फ़ंक्शन का उपयोग करके first.php में एक second.php फ़ाइल लोड किया

$ (" ("आईडी")}; // चेतावनी ("दृश्य" क्लिक किया गया ");});

second.php पहले.फिप फाइल की सफलता में दूसरी पीएचपी सामग्री लोड किया गया।

लेकिन second.php में कुछ jquery फ़ंक्शन शामिल हैं ... दूसरे में Php

$ (दस्तावेज़) .ready (फ़ंक्शन () {चेतावनी ("दूसरा दस्तावेज़ jquery");});

यह काम नहीं कर रहा है ... और इस पीठ पर वापस जाना जावास्क्रिप्ट भी पहले काम नहीं कर रहा है जब first.php में लोड होता है, लेकिन दोनों सीधे काम करते समय second.php कॉल करते हैं

क्या करें

आपकी दूसरी फ़ाइल & mdash; जो मुझे लगता है कि HTML का एक टुकड़ा है और एक पूर्ण दस्तावेज़ नहीं है & mdash; एक "तैयार" ईवेंट प्राप्त नहीं कर रहा है, क्योंकि आप सिर्फ डोम को संशोधित कर रहे हैं। यदि आपको चलाने के लिए कुछ एम्बेडेड जावास्क्रिप्ट की आवश्यकता है, तो इसे सीधे टैग के अंत में एक टैग में डाल दें: 

  & lt; div id = 'stuff' & gt; & Lt;! - ... --- & gt; & Lt; / div & gt; & LT; स्क्रिप्ट & gt; चेतावनी ("हाय मैं सिर्फ लोड किया गया है"); & Lt; / स्क्रिप्ट & gt;

jQuery सुनिश्चित करेगा कि जावास्क्रिप्ट ब्लॉक तब चलाता है जब टुकड़ा DOM में जोड़ा जाता है।


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