perl - VIM 7.2 Scripting problem with `:perldo` and multiple expressions -

background work

To end XY issues, I would say what I'm doing: I is trying to use : perldo in VIM 7.2 to complete two tasks:

• Clear all the backward whitespace, in which (not clearing ) The removal lines are only white space
  • s / \ s + $ //;
  • Before non-non-space characters
    • s / ^ (\s *) (? = \ S) / S # [^ \ t] ## g; $ _ / Xe;

      I want to do all this one pass right now, by using : perldo I can work with two passes. (Using: twice daily)

      The command should look like this:

       : perldo s / \ s + $ //; S / ^ (\ s *) (? = \ S) / s # [^ \ t] ## g; $ _ / Xe;  

      pearl background

      To understand this problem you should know something about Perl s /// automatically defaults The variable binds the variable $ _ which is free to modify the regedx. Most of the main functions work on default at $ _ .

      perl -e '$ _ = "foo"; S / foo / bar /; S / bar / baz /; The impression is that you can use the expression in the VIM using the : perldo and it is logical to print the ' # print baz

      Will work as usual.

      Vime is not good

      Now my VIM problem has been improved with the code - I've reduced it in a simple test. Open a new buffer, place the following text in it:

        aa bb aa bb  

      to run it now : perldo s / a / z /; S / b / z /; buffer is now in:

        za zb aa zb  

      the second regox failed row, and yet another regex was successful by itself , And on the first line?

It appears that the entire parall expression that passes through : perldo A true / defined value must be returned, or the results are removed, per-line

try it, nothing happens on any line:

 : Perldo s / a / z /; S / b / z /; 0  

Try it, it works on all 3 lines as expected:

 : perldo s / a / z /; S / b / z; An example in 1  

: perldo indicates:

 : perldo $ _ = reverse ($ _) ; 1  

But unfortunately it does not say clearly what is happening.