php - How to increment count in the replacement string when using preg_replace? -


मेरे पास यह कोड है: 

  $ count = 0; Preg_replace ('/ test /', 'test'। $ Count, $ सामग्री, -1, $ count);

हर जगह के लिए, मैं test0 प्राप्त करता हूँ

मैं test0, test1, test2 आदि प्राप्त करना चाहूंगा।

उपयोग करें : 

  $ count = 0; Preg_replace_callback ('/ test /', 'rep_count', $ सामग्री); समारोह rep_count ($ मैचों) {वैश्विक $ गिनती; वापसी 'परीक्षा' $ गिनती ++; }

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