Help understanding multidimensional array and pointer notation in c++ -


I understand the basic idea that when an array is the only operam & amp; Or sizeof () operator, it decays an indicator for the first element in the array. I am unsure about how these notations work. In our lessons, there are 1-D cases, 3-D cases versus an array The first example is the function for the function, which is called normal. 1-D case 

  Double average (double set []) or double average (double * set)

Not equal multi-d case Announcement 

  Double average [] [DIM1] [DIM2]) or double average (double (* set) [DIM1] [DIM2])  < Similarly, the function declaration for printing a value for 1-D: 
 
  double * print value (double value)  
 < P> D is the case: 
 
 Double (* print value (double value) [DIM1] [DIM2] 
 
 Does anyone have any questions on this Can you put light? Thank you.

parameter still decays important for an indicator is that the size of DIM 1 and DIM2 all Specify, but one dimension Therefore, if we have: 

  Double average (double set [] [DIM1] [DIM2] MySet)

MySset [0] [0] Together with DIM2 * size (double) MySet [0] [1], two dimensions say that mileage [1] before mileage [0] is DIM 1 * DIM2 * size (double) I left you And a DIM0 is not required, because the number of rows does not affect indicative arithmetic. You can always leave the left dimension for this reason.


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