sql - Round date to 10 minutes interval -


I have a DATE column that I want to round at the next 10 minute intervals Am a query (see example below).

I managed to do it by deducting the last digit of minutes by reducing it in seconds. Test_data AS (SELECT TO_DATE (SELECT TO_DATE '2010-01-01 10:00:00', 'YYYY-MM-DD HH24: MI: SS') d with double team selected TO_DATE 

  From ('2010-01-01 10:05:00', 'YYYY-MM-DD HH 24: MI: SS') d Dual union selection from TO_DATE ('2010-01-01 10:09:59', ' Dual union selective TO_DATE ('2010-01-01 10:10:00', 'YYYY-MM-DD HH24: MI: SS') d from DY-YY-MM-DD HH 24: MI: SS ') d Association selected from TO_DATE ('2099-01-01 10:00:33', 'YYYY-MM-DD HH 24: MI: SS') d) Double-select test-data #end D, TRUN ( D, 'MI') - TO_CHA R (D, 'MI'), 10) / (24 * 60) from Test_data   
 And here's the result:  
 
 01.01.2010 10 :  00:00  & nbsp; & Nbsp; 01.01.2010 10:  00:00  
 01.01.2010 10:  05:00  & nbsp; & Nbsp; 01.01.2010 10:  00:00  
 01.01.2010 10:  09:59  & nbsp; & Nbsp; 01.01.2010 10:  00:00  
 01.01.2010 10:  10:00  & nbsp; & Nbsp; 01.01.2010 10:  10:00  
 01.01.20 99 10:  00:33  & nbsp; & Nbsp; 01.01.20 99 10:  00:00    
 Works as expected, but is there a better way?  
  Edit :  
 I was curious about the display, so I did the following tests with 500,000 rows and (in fact) not random dates. I want to add results as comments for the solutions provided.  
  Translated time TIMESTAMP: = SYSTIMESTAMP; (IMI) - Choose TODCAR (D, 'MI'), 10) / IOA (as test_data AS (SELECT SYSDATE + ROWNUM / 5000 D to ROWNUM with double connection = 500000) TRUNC (D , 'MI') (24 * 60) from test_data) Loop Nouvelle; End loop; Dbms_output.put_line (SYSTIMESTAMP -T); End;  
 
 This approach received  03.24 s . 
 

 select  trunc (sysdate, 'mi') - numtodsinterval (mod (EXTRACT) ( Dual; minutes (sysdate as timestamp), 10), 'min'); Select trunc (sysdate, 'mi') - mod (excitat (sysdate as timestamp), 10) / or  
  (24 * 60) from dual ;

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