sql server 2005 - SQL Query, SELECT Top 2 by Foreign Key Order By Date -


I need a SQL query that gives the top 2 plans PlanDate per client ID Is on a table where Planetida is the primary ID, ClientID is a foreign id

this is what I have yet -> 

  SELECT * FROM [dbo]. [TblPlan] where [PlanID] IN (SELECT TOP (2) PlanID FROM [DBO]. [TblPlan] Order [PlanDate] DESC), of course, only two records are sent. Where I actually have 2 records per  ClientID .

This can be done using ROW_NUMBER: 

  SELECT PlanId, ClientId, PlanData (Select ROW_NUMBER () (Particular by Client Id Order by Planner DESC) RN, * FOR [DBO]. [TBPLAN]) AS T1 WHERE RN & LT; = 2

You will have to select any other column to get them.


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